#include <iostream>
#include <string>
#include<unordered_map>
using namespace std;
void printMap(const unordered_map<int, int> m){
for(auto item:m){
cout<< item.first << " " << item.second<<" ";
cout<< item.first << " " << m[item.first]<<endl;
//cout<< item.first << " " << m.at(item.first)<<endl;
}
return;
}
int main()
{
unordered_map<int, int> m;
m[0]=10;
m[1]=20;
printMap(m);
return 0;
}
Question: How to solve the following error:
9:49: error: passing 'const std::unordered_map<int, int>' as 'this' argument of
'std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::mapped_type&
std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::operator[](const key_type&)
[with _Key = int; _Tp = int; _Hash = std::hash<int>; _Pred = std::equal_to<int>;
_Alloc = std::allocator<std::pair<const int, int> >;
std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::mapped_type = int;
std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::key_type = int]'
discards qualifiers [-fpermissive]
Answer:
using at() to access the element of map or unordered_map
Solution:
cpp.sh/7rmyz
'std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::mapped_type&
std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::operator[](const key_type&)
[with _Key = int; _Tp = int; _Hash = std::hash<int>; _Pred = std::equal_to<int>;
_Alloc = std::allocator<std::pair<const int, int> >;
std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::mapped_type = int;
std::unordered_map<_Key, _Tp, _Hash, _Pred, _Alloc>::key_type = int]'
discards qualifiers [-fpermissive]
Answer:
using at() to access the element of map or unordered_map
Solution:
cpp.sh/7rmyz
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