杭州Rokid团队是什么？ - 机器人 - 知乎

杭州Rokid团队是什么？ - 机器人 - 知乎:



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客中守岁（在柳家庄） -- 唐代春运

客中守岁（在柳家庄）

(评分人数不足)

朝代：唐代

作者：白居易

原文：

守岁尊无酒，思乡泪满巾。始知为客苦，不及在家贫。

畏老偏惊节，防愁预恶春。故园今夜里，应念未归人

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Depth First Traversal or DFS for a Graph

Reference:

http://www.geeksforgeeks.org/depth-first-traversal-for-a-graph/





// C++ program to print DFS traversal for a given given graph

#include<iostream>

#include<list>

#include<algorithm>

using namespace std;



class Graph

{

    int V;    // No. of vertices

    list<int> *adj;    // Pointer to an array containing adjacency lists

    void DFSUtil(int v, bool visited[]);  // A function used by DFS

public:

    Graph(int V);   // Constructor

    void addEdge(int v, int w);   // function to add an edge to graph

    void DFS();    // prints DFS traversal of the complete graph

    void DFS(int v);

};



Graph::Graph(int V)

{

    this->V = V;

    adj = new list<int>[V];

}



void Graph::addEdge(int v, int w)

{

    adj[v].push_back(w); // Add w to v’s list.

}



void Graph::DFSUtil(int v, bool visited[])

{

    // Mark the current node as visited and print it

    visited[v] = true;

    cout << v << " ";



    // Recur for all the vertices adjacent to this vertex

    list<int>::iterator i;

    for(i = adj[v].begin(); i != adj[v].end(); ++i)

        if(!visited[*i])

            DFSUtil(*i, visited);

}



// DFS traversal of the vertices reachable from v.

// It uses recursive DFSUtil()

void Graph::DFS(int v)

{

    // Mark all the vertices as not visited

    bool *visited = new bool[V];

    for (int i = 0; i < V; i++)

        visited[i] = false;



    // Call the recursive helper function to print DFS traversal

    // starting from specified vertix v

    DFSUtil(v, visited);

}





// The function to do DFS traversal. It uses recursive DFSUtil()

void Graph::DFS()

{

    // Mark all the vertices as not visited

    bool *visited = new bool[V];

    for (int i = 0; i < V; i++)

        visited[i] = false;



    // Call the recursive helper function to print DFS traversal

    // starting from all vertices one by one

    for (int i = 0; i < V; i++){

        std::fill_n(visited, V, false); //reset all elements to false

        if (visited[i] == false){

            cout<<"starting node="<<i<<":";

            DFSUtil(i, visited);      

        }

        cout<<endl;

     }

}





int main()

{

    // Create a graph given in the above diagram

    const int V = 4;

    Graph g(V);

    g.addEdge(0, 1);

    g.addEdge(0, 2);

    g.addEdge(1, 2);

    g.addEdge(2, 0);

    g.addEdge(2, 3);

    g.addEdge(3, 3);



    cout << "\nFollowing is DFS Traversal result when tarting at node 2:\n";

    g.DFS(2);

    cout << "\nFollowing is DFS Traversal result when starting at each node 0~"<< V<<":\n";

    g.DFS( );





    return 0;

}



//Result is:

Following is DFS Traversal result when tarting at node 2:

2 0 1 3

Following is DFS Traversal result when starting at each node 0~4:

starting node=0:0 1 2 3

starting node=1:1 2 0 3

starting node=2:2 0 1 3

starting node=3:3



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Resident Alien Claiming a Treaty Exemption for a Scholarship or Fellowship

Resident Alien Claiming a Treaty Exemption for a Scholarship or Fellowship:



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澜声科技有限公司

澜声科技有限公司:



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广告配音_广告配音服务_合成配音-配音阁,国内最专业的广告配音平台

广告配音_广告配音服务_合成配音-配音阁,国内最专业的广告配音平台:



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TensorFlow极速入门 | 雷锋网

TensorFlow极速入门 | 雷锋网:



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(2) What is the best text to speech software? - Quora

(2) What is the best text to speech software? - Quora: " Best five Text to speech voices for male "



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微信摇一摇电视的技术原理是什么？有没有相类似的APP? - 支付宝 - 知乎

微信摇一摇电视的技术原理是什么？有没有相类似的APP? - 支付宝 - 知乎: "。而国内多是在18KHz以上的频率范围嵌入水印，是因为目前常用的音频频率范围为CD的不高于为22.05KHz、电视台和DVD不高于24KH"



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Kaldi的I/O机制 | Chinese Doc of Kaldi

Kaldi的I/O机制 | Chinese Doc of Kaldi:



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algorithms/theory.md at master · skseth/algorithms

algorithms/theory.md at master · skseth/algorithms:



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How can I become an expert at C++ quickly? - programming learning knowledge | Ask MetaFilter

How can I become an expert at C++ quickly? - programming learning knowledge | Ask MetaFilter:



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As a programmer, what things impress on a resume?

https://www.quora.com/As-a-programmer-what-things-impress-on-a-resume/answer/Eric-Green-39

Neither a PhD, nor having worked at a big tech company have ever impressed me as a hiring manager.

First of all, with all respect to everyone I know who has done a PhD and has been exceptionally successful, I actually believe that having a PhD correlates negatively with being a good programmer. One needs to really differentiate between people who have a PhD in a field and are doing programming applied to that field vs. people who just have a PhD (including a PhD in computer science). The first can be exceptionally valuable if the field in question intersects with your business, however one should not be valuing these people for their programming skills but rather everything else they bring to the table. On the other hand, when I see that someone just did a PhD and then went on to writing code for a software shop, I really question why did they not do that right out of undergrad. Oftentimes the answers are not great.

Now, a big tech company has some real value on a resume: it’s basically a filter that tells you that this person meets some minimum technical competency. Basically they’re not going to be terrible. But that’s not really what I consider “impressing”.

Here are some things that I’ve learned to be impressed by:

• People who have built something, preferrably impactful and specific. Someone who owned a feature or a product from it’s inception all the way into production is going to catch my eye.
• Serious technical leadership. Someone who’s been a tech lead on a serious project (preferably big and impactful). Usually this also means seeing the word “architect” on a resume and some evidence that the person is not bullshitting.
• Lack of formal education or little of it. Now I don’t want to be anti-intellectual here and I’m not suggesting that simply lacking and education is a good thing. What I mean is when I receive a resume that looks strong and then I notice that the person in question went to some really mediocre school, or better yet, have no higher education, I am usually impressed. As I said above, I don’t find PhD’s impressive at all. More importantly if a candidate has a PhD that lowers the amount of information I can get from the rest of his resume. You see, if someone did a PhD and then went to Google or some other respectable place, that doesn’t tell me much because their PhD likely helped them get in. If someone went to a community college in Bumblefuck Missouri and then got hired at Google I want to talk to them ASAP.
• Cool hobbies and skills. Jobs that are not just software engineering. Look we all know you like to play board games and do Trivia Night. All of my guys (and yeah, they’re mostly guys) do. What I’ve found is that often you can bring some serious value to a software shop by hiring people who are not your typical software engineer. When those people also happen to be good software engineers you’ve really hit the jackpot.

Google C++ Style Guide

Google C++ Style Guide:



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谷歌云官方：一小时掌握深度学习和TensorFlow（视频+50PPT） | 新智元 | 数据观 | 中国大数据产业观察_大数据门户

谷歌云官方：一小时掌握深度学习和TensorFlow（视频+50PPT） | 新智元 | 数据观 | 中国大数据产业观察_大数据门户:



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Passing Arrays By Reference (debug)

Passing Arrays By Reference - C++ Forum:


Question:
One example about passing arrays by reference in c++ was provided in:
http://www.cplusplus.com/forum/beginner/30698/
Unfortunately, it is buggy. How can you solve it?

Answer:

#include <iostream>
#include <fstream>
#include <cstdlib>
using namespace std;

int readFile(int, int &count, int (&grades) [10]);
int writeFile(int (&grades) [10]);
int averageGrades(int, int);

/**********************************************************************
* Reads an external file of grades and then returns those values to
* other functions in the program.
*********************************************************************/
int readFile(int sum, int &count, int (&grades) [10])
{
   //Declare variable
   char sourceFile[16];
   ifstream inStream;

   //Asking for user input
   cout << "Source file: ";
   cin >> sourceFile;

   //Open file
   inStream.open(sourceFile);
   if (inStream.fail())
   {
      cout << "Input file opening failed.\n";
      exit(1);
   }

   //Read from file and place in array
   for (int i = 0; i < 10 && inStream >> grades[i]; i++)
   {
      if (grades[i] == -1)
      {
         count++;
      }

      if (grades[i] != -1)
      {
         sum += grades[i];
      }
   }
   return sum;
}

/**********************************************************************
 * Reads an external file of grades and then returns those values to
 * other functions in the program.
 *********************************************************************/
int writeFile(int (&grades) [10])
{
   ofstream outStream;
   char destinationFile[16];

   //Asking for user input
   cout << "Destination file: ";
   cin >> destinationFile;

   //Open file
   outStream.open(destinationFile);
   if (outStream.fail())
   {
      cout << "Output file opening failed.\n";
      exit(1);
   }
   for(auto i: grades)
       outStream << i<<endl;

   return 0;
}


/**********************************************************************
* Finds the average of the ten grades from the previous function.
***********************************************************************/
int averageGrades(int sum, int count, int average)
{
   //The magic formula to find the average
   if (count == 10)
   {
      cout << "Average Grade: ---%" << endl;
   }

   else
   {
      average = (sum / (10 - count));
      cout << "Average Grade: " << average << "%" << endl;
   }

   return average;
}


/**********************************************************************
* Basically a delegator. Calls other functions to do its dirty work.
***********************************************************************/
int main()
{
   //Declaring Variables
   int average = 0;
   int sum = 0;
   int count = 0;
   int grades[10];

   //Calling other functions
   sum = readFile(sum, count, grades);
   average = averageGrades(sum, count, average);
   writeFile(grades);
   return 0;
}